(4m+n)(2m^2-3mn+8n^2)

2 min read Jun 16, 2024
(4m+n)(2m^2-3mn+8n^2)

Multiplying Binomials: (4m + n)(2m² - 3mn + 8n²)

This article will explore the multiplication of the binomials (4m + n) and (2m² - 3mn + 8n²). We will use the distributive property to expand the product and simplify the resulting expression.

Understanding the Distributive Property

The distributive property states that for any numbers a, b, and c:

a(b + c) = ab + ac

This property allows us to multiply a sum by a number by distributing the multiplication to each term inside the parentheses.

Expanding the Product

To expand (4m + n)(2m² - 3mn + 8n²), we need to distribute each term in the first binomial to every term in the second binomial.

Step 1: Distribute 4m.

4m(2m² - 3mn + 8n²) = 8m³ - 12m²n + 32mn² 

Step 2: Distribute n.

n(2m² - 3mn + 8n²) = 2m²n - 3mn² + 8n³

Step 3: Combine the results of Step 1 and Step 2.

(4m + n)(2m² - 3mn + 8n²) = (8m³ - 12m²n + 32mn²) + (2m²n - 3mn² + 8n³)

Step 4: Simplify by combining like terms.

(4m + n)(2m² - 3mn + 8n²) = **8m³ - 10m²n + 29mn² + 8n³** 

Conclusion

Therefore, the product of (4m + n) and (2m² - 3mn + 8n²) is 8m³ - 10m²n + 29mn² + 8n³. By applying the distributive property and combining like terms, we successfully expanded the product and obtained a simplified expression.

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